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This topic created in 3431 days ago, the information mentioned may be changed or developed.

s = ['0.3','1.25','12.98','2']

s=map(lambda x:format(float(x),'>5.2f'),s)

print(list(s))

#[' 0.30', ' 1.25', '12.98', ' 2.00']

转化后还是字符串，格式类似>5.2f，后面不足的补0，前面不足的补空格

lambda

float

Format

7 replies • 2016-12-04 23:02:08 +08:00

explist

Dec 4, 2016

有没有什么格式可以一步到位的？

suspended

Dec 4, 2016

看我大 ruby 一句话搞掂：
```ruby
irb(main):007:0> ['0.3','1.25','12.98','2'].map {|x| '% 2.2f' % x.to_f}
=> [" 0.30", " 1.25", " 12.98", " 2.00"]
```

suspended

Dec 4, 2016

搞错。。。啊，不能删 /改回复？ - -!

thekoc

Dec 4, 2016

@explist 什么叫一步到位

Kisesy

Dec 4, 2016

print(['%5.2f'%float(x) for x in ['0.3','1.25','12.98','2']])
一行到位

explist

Dec 4, 2016

直接用格式化的相关函数如 format(),zfill()等

lonelinsky

Dec 4, 2016

[ '{: >5.2f}'.format(float(x)) for x in s ] 这个应该可以

格式化字符串疑问

转化后还是字符串，格式类似>5.2f，后面不足的补0，前面不足的补空格