假如我现在有两个链表 A, B
A 链表: 1 -> 3 -> 5
B 链表: 2 -> 4 -> 6
最终合并结果是 链表: 1 -> 2 -> 3 -> 4 -> 5 -> 6 该如何做?
假如我现在有两个链表 A, B
A 链表: 1 -> 3 -> 5
B 链表: 2 -> 4 -> 6
最终合并结果是 链表: 1 -> 2 -> 3 -> 4 -> 5 -> 6 该如何做?
1
frandy Sep 6, 2018
a = [1,3,5]
b = [2,4,6] c = a+b c.sort() print(c) |
2
meik2333 Sep 6, 2018
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
if (l1 == nullptr) { return l2; } else if (l2 == nullptr) { return l1; } auto *head = new ListNode(0); auto *cur = head; while (l1 and l2) { if (l1->val < l2->val) { cur->next = l1; l1 = l1->next; } else { cur->next = l2; l2 = l2->next; } cur = cur->next; } cur->next = l1 ? l1 : l2; cur = head->next; delete head; return cur; } |
4
ihainan Sep 6, 2018 via iPhone
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5
dbw9580 Sep 6, 2018 via Android
list(itertools.chain.from_iterable(zip(a,b)))
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6
zyp0921 Sep 6, 2018
比大小呗- -
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7
anonymous256 Sep 6, 2018 via Android
c = [*a, *b]
c.sort() print(c) |
8
seven2016 Sep 6, 2018
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9
someonedeng Sep 6, 2018 作业要自己做。
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10
stargazer Sep 6, 2018
合并有序链表,,,
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11
tt67wq Sep 7, 2018
归并排序似乎就是这个
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12
Cukuyo Sep 7, 2018
作业要自己做
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