JWT token - V2EX

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字符串（字母加数字）自增问题：
字符串 str=“ NB0001 ”；
然后要得到“ NB0002 ”
怎么算啊，如果不截的话

字符

nb0002

nb0001

jwt

1 replies • 2018-11-10 23:58:28 +08:00

Aidenboss

Nov 10, 2018

Pattern pattern = Pattern("([0-9]+)");
Matcher matcher = pattern.compile(pattern, str);
if (matcher.find()) {
long number = NumberUtils.toLong(matcher.group(1));
}