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This topic created in 2720 days ago, the information mentioned may be changed or developed.
这条语句用于实现无论查找件号，还是查找描述，只要完全匹配，则后续通过 df.loc 列出结果，这个没问题 df['group'] = np.where((df['code'] == keystring) | (df['description'] == keystring), 'hit', 'nohit')
目前希望改进为，关键字的部分内容匹配序列中内容，就列出，相当于模糊查询，pycharm 没报错，但是不生效 df['group'] = np.where((keystring in df['code']) | (keystring in df['description']), 'hit', 'nohit')
求教问题出在哪里
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1
billgreen1 Nov 15, 2018  1
keystring in df['code'] 有点类似 'a' in ['a', 'b','c']
你需要的是 df['ocde'].str.contains(keystring) |
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2
ruoyu0088 Nov 15, 2018 1
用这个试试看：
df["code"].str.contains(keystring) | df["description"].str.contains(keystring) |
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3
youthfire OP 感觉两位的解释和纠正，已测，确实可行。
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