roshad
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求能卡死有 无限循环检测机制的 网页的代码

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  •   roshad · Aug 19, 2019 · 1942 views
    This topic created in 2485 days ago, the information mentioned may be changed or developed.
    roshad
        1
    roshad  
    OP
       Aug 19, 2019
    function sumFibs(num) {
    var fib =(num)=>{
    if (num<3) return 1
    return fib(num-1)+fib(num-2)
    }
    var sum =0;

    for (var i=1;fib(i)<=num;i++){
    if (fib(i)%2!=0) sum+=fib(i)
    }

    return sum
    }
    很低效的求 fib,数字够大能卡死一段时间。
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