一段Python解密题

def squarer(value, key):
if len(value) % 2 == 0:
p = int(round(len(value)) / 2.0)
value = reversed(value[-p:]) + reversed(value[:p])
k = 0
result = ''
for v in value:
if ord(v) ^ ord(key[k]) < 32 | ord(v) ^ ord(key[k]) > 126 | ord(v) < 0 | ord(v) > 255:
result += v
else:
result += chr(ord(v) ^ ord(key[k]))
k = 0 if k == len(key) else k + 1
return result

print(squarer('ma=cjy', '???'))

输出结果是xamyjc

求 ???