面试前猎头提示我会考递归，妈的，现学真的搞不定啊，题目是 li = [2,3,5,7,9]，输出任意组合，可以重复选，输出所有和是 13 的组合，递归现学现用失败，还是老老实实拿循环写的：
li = [2,3,5,7,9]
def sum13(li):
for i in li:
if i == 13:
print(i)
for j in li:
if i + j == 13:
print(i,j)
for k in li:
if i + j + k== 13:
print(i,j,k)
for l in li:
if i + j + k + l== 13:
print(i,j,k,l)
for o in li:
if i + j + k + l + o == 13:
print(i,j,k,l,o)
我这是面不过了吧？
li = [2,3,5,7,9]
def sum13(li):
for i in li:
if i == 13:
print(i)
for j in li:
if i + j == 13:
print(i,j)
for k in li:
if i + j + k== 13:
print(i,j,k)
for l in li:
if i + j + k + l== 13:
print(i,j,k,l)
for o in li:
if i + j + k + l + o == 13:
print(i,j,k,l,o)
我这是面不过了吧？
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